document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=523741>Question 523741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A speeding boat traveled a distance of X km at a constant speed of 80km/h. An ocean liner traveled the same distance in 60km/h. If the difference in time was 2 hours, calculate X </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347400 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> time by ocean liner -time by speeding boat= 2\r<BR>\n" );
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document.write( "t=d/r<BR>\n" );
document.write( "x/60-x/80=2<BR>\n" );
document.write( "LCD = 240<BR>\n" );
document.write( "multiply by LCD<BR>\n" );
document.write( "4x-3x=240*2<BR>\n" );
document.write( "x=480 miles\r<BR>\n" );
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