document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=523644>Question 523644</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the line has a slope of -2/3 and passes through (6,12) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347355 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given the line has slope -2/3 we can define the equation using slope-intercept form:<BR>\n" );
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document.write( "y = -2/3x + b<BR>\n" );
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document.write( "Use the point to find 'b'.<BR>\n" );
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document.write( "12 = -(2/3)*6 + b<BR>\n" );
document.write( "12 = -4 + b<BR>\n" );
document.write( "16 = b<BR>\n" );
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document.write( "So the equation is:<BR>\n" );
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document.write( "y = -2/3x + 16<BR>\n" );
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