document.write( "Question 523638: the sum of three numbers is 237. the second number is 9 less than two times the first number. the third number is 6 more than three times the first number. what are the three numbers? \n" ); document.write( "
Algebra.Com's Answer #347352 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! x + y + z = 237 \n" ); document.write( ". \n" ); document.write( "y = 2x -9 \n" ); document.write( ". \n" ); document.write( "z = 3x +6 \n" ); document.write( ". \n" ); document.write( "substitute \n" ); document.write( ". \n" ); document.write( "x +2x-9 +3x+6 = 237 \n" ); document.write( ". \n" ); document.write( "6x -3 = 237 \n" ); document.write( ". \n" ); document.write( "6x = 240 \n" ); document.write( ". \n" ); document.write( "x = 40 \n" ); document.write( ". \n" ); document.write( "substitute \n" ); document.write( ". \n" ); document.write( "y = 2x -9 \n" ); document.write( "y = 2*40 -9 \n" ); document.write( "y = 71 \n" ); document.write( ". \n" ); document.write( "z = 3x +6 \n" ); document.write( "z = 3*40 +6 \n" ); document.write( "z = 126 \n" ); document.write( ". \n" ); document.write( "Check the sum \n" ); document.write( ". \n" ); document.write( "40 + 71 + 126 = 237 \n" ); document.write( ". \n" ); document.write( "Answer: The three numbers are 40, 71, and 126. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |