document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=523624>Question 523624</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use log 2=.301, log 3= .699 to compute log (1/20) to the nearest three decimal places. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347344 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use log 2=.301, log 5= .699 to compute log (1/20) to the nearest three decimal places.<BR>\n" );
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document.write( "1/20 = 1/(2^2*5)<BR>\n" );
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document.write( "log(1/20) = log(20)^-1 = -log(2^2*5)<BR>\n" );
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document.write( "= -[2log(2) + log(5)]<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= -[2*0.301 + 0.699]<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= -1.3010<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "===============<BR>\n" );
document.write( " </SPAN>\n" );
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