document.write( "Question 52078This question is from textbook intermediate algebra
\n" );
document.write( ": How many liters of a 10% alcohol solution must be mixed with 40 L of a 50% solution to get a 40% solution? \n" );
document.write( "
Algebra.Com's Answer #34734 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let x = the number of liters of the 10% alcohol solution. \n" ); document.write( "From the problem description, you can write the equation: (Note: Change the percents to their decimal equivalents) The final solution will be (40+x) liters. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You will need to mix 13.33...(or 13 1/3) liters of 10% alcohol solution with 40 liters of 50% alcohol solution to obtain 53.33... (or 53 1/3) liters of 40% alcohol solution.\r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "13.33(0.1) + 40(0.5) = 53.33(0.4) \n" ); document.write( "1.333 + 20 = 21.333 \n" ); document.write( "21.333 = 21.333 \n" ); document.write( " \n" ); document.write( " |