document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52067>Question 52067</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My son has the below homework problem. I tried to help him, but it's been a while since I had algebra and I've long since forgot a lot of the rules. Any help that you can give would be more than appreciated!!\r<BR>\n" );
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document.write( "Peter says that the following equations are two ways to write the SAME formula.  Solve them both for the same variable to decide whether or not you agree with Peter.  Explain how you made your decision, based on solving for variables.  \r<BR>\n" );
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document.write( "p= (r-1)/r            p/(p+1)= r\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34733 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+%28r-1%29%2Fr ALIGN=MIDDLE  ALT=\"p+=+%28r-1%29%2Fr\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "2) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p%2F%28p%2B1%29+=+r ALIGN=MIDDLE  ALT=\"p%2F%28p%2B1%29+=+r\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Let's solve equation 2) for p and see if it matches equation 1).\r<BR>\n" );
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document.write( "2) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p%2F%28p%2B1%29+=+r ALIGN=MIDDLE  ALT=\"p%2F%28p%2B1%29+=+r\"   DISABLED_style= \"max-width:90%; height:auto;\" > Multiply both sides of the equation by (p+1).<BR>\n" );
document.write( "2a)<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+r%28p%2B1%29 ALIGN=MIDDLE  ALT=\"p+=+r%28p%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Apply the distributive property to the right side.<BR>\n" );
document.write( "2b)<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+rp%2Br ALIGN=MIDDLE  ALT=\"p+=+rp%2Br\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract rp from both sides.<BR>\n" );
document.write( "2c) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p-rp+=+r ALIGN=MIDDLE  ALT=\"p-rp+=+r\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify this by factoring out the p on the left side.<BR>\n" );
document.write( "2d) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p%281-r%29+=+r ALIGN=MIDDLE  ALT=\"p%281-r%29+=+r\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now divide both sides by (1-r).<BR>\n" );
document.write( "2e) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+r%2F%281-r%29 ALIGN=MIDDLE  ALT=\"p+=+r%2F%281-r%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > You can rewite this as:<BR>\n" );
document.write( "2f) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+-r%2F%28r-1%29 ALIGN=MIDDLE  ALT=\"p+=+-r%2F%28r-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now compare this with equation 1)<BR>\n" );
document.write( "1) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p+=+%28r-1%29%2Fr ALIGN=MIDDLE  ALT=\"p+=+%28r-1%29%2Fr\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You can see that equation 2f) is the negative reciprocal of equation 1) so Peter is incorrect in his statement. </SPAN>\n" );
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