document.write( "Question 523400: Hi,\r
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\n" ); document.write( "\n" ); document.write( "What is the number that is 9 less than twice the additive inverse?\r
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Algebra.Com's Answer #347312 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
A number plus its additive inverse = 0.
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\n" ); document.write( "What number is 9 less than twice its additive inverse.
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\n" ); document.write( "Define y is the additive inverse of x
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\n" ); document.write( "x + y = 0
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\n" ); document.write( "x = -y
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\n" ); document.write( "The number is 9 less than twice its additive inverse.
\n" ); document.write( "x+9 = 2y
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\n" ); document.write( "Substitute x = -y.
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\n" ); document.write( "-y +9 = 2y
\n" ); document.write( "9 = 3y
\n" ); document.write( "3y = 9
\n" ); document.write( "y = 3
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\n" ); document.write( "x + y = 0
\n" ); document.write( "x + 3 = 0
\n" ); document.write( "x = -3
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\n" ); document.write( "So the number is -3. its additive inverse is 3.
\n" ); document.write( "Twice the additive inverse = 2*(3) = 6.
\n" ); document.write( "-3 is indeed 9 less than 2*3.
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\n" ); document.write( "Done.
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