document.write( "Question 523386: Joe wants to build a rectangular shaped deck whose length will be three inches greater than its width. What will be the dimensions of the deck if the perimeter is to be 54 inches. \n" ); document.write( "

Algebra.Com's Answer #347307 by oberobic(2304) $\"\"$ $\"About$

You can put this solution on YOUR website!
P = perimeter
\n" ); document.write( "P = 54 in.
\n" ); document.write( "P = 2(L+W), where L=Length and W=Width
\n" ); document.write( ".
\n" ); document.write( "L = W+3
\n" ); document.write( ".
\n" ); document.write( "substitute
\n" ); document.write( ".
\n" ); document.write( "2(W+3) + 2W = 54
\n" ); document.write( ".
\n" ); document.write( "2W +6 +2W = 54
\n" ); document.write( ".
\n" ); document.write( "4W = 48
\n" ); document.write( ".
\n" ); document.write( "W = 12
\n" ); document.write( ".
\n" ); document.write( "L = W+3
\n" ); document.write( "L = 12+3
\n" ); document.write( "L = 15
\n" ); document.write( ".
\n" ); document.write( "Check the perimeter to be sure this solution is the answer.
\n" ); document.write( ".
\n" ); document.write( "2L = 2(15) = 30
\n" ); document.write( "2W = 2(12) = 24
\n" ); document.write( "30+24 = 54
\n" ); document.write( "Correct.
\n" ); document.write( ".
\n" ); document.write( "Answer: Length = 15 inches; Width = 12 inches.
\n" ); document.write( ".
\n" ); document.write( "Is this a deck for a doll house? Just wondering...(smile)
\n" ); document.write( " \n" ); document.write( "

\n" );