document.write( "Question 523347: A basketball team's star 3-point shooter takes six 3- point shots in a game. Historically, he makes 40% of all 3-point shots taken in a game. State at the outset what assumptions you have made.\r
\n" );
document.write( "\n" );
document.write( "(a) Find the probability that at least two shots were made.
\n" );
document.write( "(b) Find the probability that exactly three shots were made.
\n" );
document.write( "(c) Find the mean and standard deviation of the num¬ber of shots made.
\n" );
document.write( "(d) Find the mean and standard deviation of the total number of points scored as a result of these shots.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #347300 by stanbon(75887) ![]() You can put this solution on YOUR website! A basketball team's star 3-point shooter takes six 3- point shots in a game. Historically, he makes 40% of all 3-point shots taken in a game. State at the outset what assumptions you have made. \n" ); document.write( "Independent trials; binomial results; \n" ); document.write( "------ \n" ); document.write( "(a) Find the probability that at least two shots were made. \n" ); document.write( "P(2<= x <= 6) = 1 - binomcdf(6,0.4,1) = 0.7667 \n" ); document.write( "----------------------------------------------------------- \n" ); document.write( "(b) Find the probability that exactly three shots were made. \n" ); document.write( "P(x = 3) = 6C3*0.4^3*0.6^3 = 0.2765 \n" ); document.write( "----------------------------------------------------------- \n" ); document.write( "(c) Find the mean and standard deviation of the num¬ber of shots made. \n" ); document.write( "mean = np = 6*0.4 = 2.4 \n" ); document.write( "std = sqrt(npq) = sqrt(2.4*0.6) = 1.2 \n" ); document.write( "---------------------------------------------- \n" ); document.write( "(d) Find the mean and standard deviation of the total number of points scored as a result of these shots. \n" ); document.write( "mean # of points: 2.4*3 = 7.2 \n" ); document.write( "std of # of points: 1.2*3 = 3.6 \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |