document.write( "Question 523291: Mabel's salary starts at $16,000 per year with annual raises of $1500. Janet's starting salary is $19,300 with annual raises of $950. After how many years will the two women be earning the same salary? \n" ); document.write( "
Algebra.Com's Answer #347292 by Maths68(1474) You can put this solution on YOUR website! Let \n" ); document.write( "It takes = x years\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Mabel's slary 16,000 \n" ); document.write( "Annual raise = 1500\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Janet's Salary = 19300 \n" ); document.write( "Annual raise = 950\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "16000+ 1500*x = 19300 + 950*x \n" ); document.write( "1500x-950x=19300-16000 \n" ); document.write( "550x=3300 \n" ); document.write( "550x/550=3300/550 \n" ); document.write( "x=6\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 6 years they will be earning same salary.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "======\r \n" ); document.write( "\n" ); document.write( "16000+ 1500*x = 19300 + 950*x \n" ); document.write( "16000 + 1500 * 6 = 19300 + 950*6 \n" ); document.write( "16000 + 9000 = 19300+5700 \n" ); document.write( "25000 = 25000 \n" ); document.write( " |