document.write( "Question 523104: Solve the equation on the interval 0 < theta < 2pi\r
\n" ); document.write( "\n" ); document.write( "cot 2theta/3 = -sqrt3
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Algebra.Com's Answer #347249 by lwsshak3(11628)\"\" \"About 
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Solve the equation on the interval 0 < theta < 2pi
\n" ); document.write( "cot 2theta/3 = -sqrt3
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\n" ); document.write( "using x in place of theta
\n" ); document.write( "cot(2x/3)=-√3
\n" ); document.write( "2x/3=5π/6 and 11π/6 (reference angles of π/6 in quadrants II and IV where cot<0)
\n" ); document.write( "2x/3=5π/6
\n" ); document.write( "2x=15π/6
\n" ); document.write( "x=15π/12=5π/4
\n" ); document.write( "and
\n" ); document.write( "2x/3=11π/6
\n" ); document.write( "2x=33π/6
\n" ); document.write( "x=33π/12=11π/4
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