document.write( "Question 523225: Could you please show me how to graph this problem?\r
\n" ); document.write( "\n" ); document.write( "y=1/3x-4 and 3y-x=4
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Algebra.Com's Answer #347245 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Could you please show me how to graph this problem?
\n" ); document.write( "y=1/3x-4 and 3y-x=4
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\n" ); document.write( "These two equations are of straight lines of standard form: y=
\n" ); document.write( "+b, m=slope, b=y-intercept.
\n" ); document.write( "To graph these lines, equations should be in standard form.
\n" ); document.write( "The first equation, y=(1/3)x-4 is already in standard form.
\n" ); document.write( "Changing second equation into standard form:
\n" ); document.write( "3y-x=4
\n" ); document.write( "3y=x+4
\n" ); document.write( "y=x/3+4
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\n" ); document.write( "Only two points are needed to graph the line
\n" ); document.write( "For first equation, the y-intercept=-4, so you have one point at (0,-4)
\n" ); document.write( "To find the second point, use the slope=1/3=rise/run=∆y/∆x
\n" ); document.write( "From the y-intercept (0,-4) move up one unit and 3 units to the right which gives you the second point at (3,-3). The graph of the line go thru these two points (0,-4)
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\n" ); document.write( "Graphing the line of the second equation is with the same slope but the y-intercept is 4 instead of
\n" ); document.write( "-4. You should end up with two lines parallel to each other with slopes of 1/3
\n" ); document.write( "see the graph below as a visual check on your graphs
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\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+x%2F3-4%2Cx%2F3%2B4%29+\"
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