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what is the standard form of the equation of the line passing through the point (-2,-2) and perpindicular to the line 3x-5y=-5 ?\r
\n" ); document.write( "\n" ); document.write( "Standard Form of Equation of the line:
\n" ); document.write( "y=mx+b
\n" ); document.write( "Given
\n" ); document.write( "3x-5y=-5
\n" ); document.write( "rearrage the above equation according to the standard form
\n" ); document.write( "-5y=-3x-5
\n" ); document.write( "-5y/-5=-(3x+5)/-5
\n" ); document.write( "y=3/5(x)+1
\n" ); document.write( "Compare above equation with the standard form equation
\n" ); document.write( "m=3/5 and b=1
\n" ); document.write( "Since lines are perpendicular multiplicatin of their slope will be (-1)
\n" ); document.write( "So slope of the required line will be (-5/3)
\n" ); document.write( "Now we have a point(-2,-2) and slope (-5/3)of the line we can easily find required lines by putting these values in the equation of the straight line poin-slope form.
\n" ); document.write( "m=(y2-y1)/(x2-x1)
\n" ); document.write( "-5/3=(y-(-2))/(x-(-2))
\n" ); document.write( "-5/3=(y+2))/(x+2)
\n" ); document.write( "-5(x+2)=3(y+2)
\n" ); document.write( "-5x-10=3y+6
\n" ); document.write( "-3y=5x+10+6
\n" ); document.write( "-3y=5x+16
\n" ); document.write( "-3y/-3 = (5x+16)/-3
\n" ); document.write( "y=-5/3(x)-16/3
\n" ); document.write( "Above equation is the required equation of the line in standard Form.
\n" ); document.write( "Red line = Given line
\n" ); document.write( "Green line = Required line
\n" ); document.write( "