document.write( "Question 523129: Trais made a business trip of 234 miles. He averaged 54 mph for the first part of the trip and 60 mph for the second part. If the trip took 4 hours, how long did he travel at each rate? \n" ); document.write( "
Algebra.Com's Answer #347196 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
a business trip of 234 miles. He averaged 54 mph for the first part of the trip and 60 mph for the second part.
\n" ); document.write( " If the trip took 4 hours, how long did he travel at each rate?
\n" ); document.write( ":
\n" ); document.write( "Let t = travel time at 60
\n" ); document.write( "then
\n" ); document.write( "(4-t) = travel time at 54
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation: dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "dist at 60 + dist at 54 = 234 mi
\n" ); document.write( "60t + 54(4-t) = 234
\n" ); document.write( "60t + 216 - 54t = 234
\n" ); document.write( "60t - 54t = 234 - 216
\n" ); document.write( "6t = 18
\n" ); document.write( "t = 18/6
\n" ); document.write( "t = 3 hrs at 60 mph
\n" ); document.write( "then
\n" ); document.write( "4 - 3 = 1 hr at 54 mph
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check by finding the distance at each speed
\n" ); document.write( "3*60 = 180
\n" ); document.write( "1*54 = 54
\n" ); document.write( "-----------
\n" ); document.write( "total: 234 mi
\n" ); document.write( " \n" ); document.write( "
\n" );