document.write( "Question 522807: A trip between two cites 175 miles apart take 1.5 hrs less than by bus. The average speed of the bus is 15 miles per hour less than the train.
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document.write( "Find the average speeds of the train and the bus. \n" );
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Algebra.Com's Answer #347167 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A trip between two cites 175 miles apart take 1.5 hrs less than by bus. \n" ); document.write( " The average speed of the bus is 15 miles per hour less than the train. \n" ); document.write( "Find the average speeds of the train and the bus. \n" ); document.write( ": \n" ); document.write( "Let s = speed of the bus \n" ); document.write( "then \n" ); document.write( "(s+15) = speed of the train \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( ": \n" ); document.write( "Train time - Bus time = 1.5 hrs \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( "multiply by s(s+15) \n" ); document.write( "s(s+15)* \n" ); document.write( ": \n" ); document.write( "Cancel out the denominators, results: \n" ); document.write( "175(s+15) - 175s = 1.5s^2 + 22.5s \n" ); document.write( "175s + 2625 - 175s = 1.5s^2 + 22.5s \n" ); document.write( ": \n" ); document.write( "a quadratic equation \n" ); document.write( "0 = 1.5s^2 + 22.5s - 2625 \n" ); document.write( "get rid of the decimals, multiply by 2 \n" ); document.write( "3s^2 + 45s - 5250 = 0 \n" ); document.write( "You can use the quadratic formula here, but this will factor to: \n" ); document.write( "(3s-105)(s+50) = 0 \n" ); document.write( "positive solution \n" ); document.write( "3s = 105 \n" ); document.write( "s = 105/3 \n" ); document.write( "s = 35 mph is the speed of the bus, \n" ); document.write( "then \n" ); document.write( "35+15 = 50 mph is the speed of the train \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the actual time of each \n" ); document.write( "175/35 = 5.0 hrs \n" ); document.write( "175/50 = 3.5 hrs \n" ); document.write( "----------------- \n" ); document.write( "differs: 1.5 hrs \n" ); document.write( " |