document.write( "Question 522807: A trip between two cites 175 miles apart take 1.5 hrs less than by bus. The average speed of the bus is 15 miles per hour less than the train.
\n" ); document.write( "Find the average speeds of the train and the bus.
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Algebra.Com's Answer #347167 by ankor@dixie-net.com(22740)\"\" \"About 
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A trip between two cites 175 miles apart take 1.5 hrs less than by bus.
\n" ); document.write( " The average speed of the bus is 15 miles per hour less than the train.
\n" ); document.write( "Find the average speeds of the train and the bus.
\n" ); document.write( ":
\n" ); document.write( "Let s = speed of the bus
\n" ); document.write( "then
\n" ); document.write( "(s+15) = speed of the train
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Train time - Bus time = 1.5 hrs
\n" ); document.write( "\"175%2Fs\" - \"175%2F%28%28s%2B15%29%29\" = 1.5
\n" ); document.write( ";
\n" ); document.write( "multiply by s(s+15)
\n" ); document.write( "s(s+15)*\"175%2Fs\" - s(s+15)*\"175%2F%28%28s%2B15%29%29\" = 1.5s(s+15)
\n" ); document.write( ":
\n" ); document.write( "Cancel out the denominators, results:
\n" ); document.write( "175(s+15) - 175s = 1.5s^2 + 22.5s
\n" ); document.write( "175s + 2625 - 175s = 1.5s^2 + 22.5s
\n" ); document.write( ":
\n" ); document.write( "a quadratic equation
\n" ); document.write( "0 = 1.5s^2 + 22.5s - 2625
\n" ); document.write( "get rid of the decimals, multiply by 2
\n" ); document.write( "3s^2 + 45s - 5250 = 0
\n" ); document.write( "You can use the quadratic formula here, but this will factor to:
\n" ); document.write( "(3s-105)(s+50) = 0
\n" ); document.write( "positive solution
\n" ); document.write( "3s = 105
\n" ); document.write( "s = 105/3
\n" ); document.write( "s = 35 mph is the speed of the bus,
\n" ); document.write( "then
\n" ); document.write( "35+15 = 50 mph is the speed of the train
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the actual time of each
\n" ); document.write( "175/35 = 5.0 hrs
\n" ); document.write( "175/50 = 3.5 hrs
\n" ); document.write( "-----------------
\n" ); document.write( "differs: 1.5 hrs
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