document.write( "Question 523005: Hi,\r
\n" ); document.write( "\n" ); document.write( "I am having problems with a chi-square related question.\r
\n" ); document.write( "\n" ); document.write( "Here is the question:\r
\n" ); document.write( "\n" ); document.write( "(a) Write the null and alternative hypothesis for a one-sided test to determine whether men are, on average, heavier than men from 20 years ago.\r
\n" ); document.write( "\n" ); document.write( "These are the hypotheses I have come up with:\r
\n" ); document.write( "\n" ); document.write( "Null Hypothesis – There is no difference between the average weight of men now and 20 years ago.
\n" ); document.write( "Alternative Hypothesis – Men, on average, are heavier than men from 20 years ago.\r
\n" ); document.write( "\n" ); document.write( "(b) Carry out a test of the hypothesis in (a) at the 5% significance level, i.e. calculate the:
\n" ); document.write( "- Test statistic
\n" ); document.write( "- Critical value of the Normal Distribution for a one-sided test at the 5% significance level\r
\n" ); document.write( "\n" ); document.write( "This is where I am having problems. I know how to do chi-square (I'm assuming we have to use chi-square as that's what we have been using in the other questions) when I have the data, ie. observed and expected. What I am unsure about is what data to use as this is all I have been provided with:\r
\n" ); document.write( "\n" ); document.write( "From data collected 20 years ago, the average weight of an adult male was 71 kilograms and the standard deviation 7.2 kilograms.\r
\n" ); document.write( "\n" ); document.write( "Table: Weights (in kilograms) of a new random sample of 29 adult males\r
\n" ); document.write( "\n" ); document.write( "59 79 61 81 62
\n" ); document.write( "82 66 68 83 69
\n" ); document.write( "84 70 73 77 84
\n" ); document.write( "74 88 76 78 91
\n" ); document.write( "78 74 86 59 66
\n" ); document.write( "73 74 75 76 \r
\n" ); document.write( "\n" ); document.write( "So far I have been using the averaging weight of the new sample of men which is 74.7 and the average weight from 20 years ago which is 71 and trying to use a one-way chi-square method. So basically my table looks like this:\r
\n" ); document.write( "\n" ); document.write( " Today 20 Years Ago
\n" ); document.write( "Weight 74.7 71\r
\n" ); document.write( "\n" ); document.write( "First of all is this the correct way of doing it? If so, my next dilemma is trying to figure out the expected frequency from the observed. I know how to calculate the expected from a contingency table of 2 or more rows, but when i try to apply the same formula to just one row, the expected ends up the same as the observed, which surely cant be right?\r
\n" ); document.write( "\n" ); document.write( "If I am going about it totally the wrong way, any advice would be appreciated. I am not a mathematician or even studying it ,so apologies for my lack of knowledge.\r
\n" ); document.write( "\n" ); document.write( "Hopefully someone can help me out.\r
\n" ); document.write( "\n" ); document.write( "Ryan
\n" ); document.write( "

Algebra.Com's Answer #347150 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
That is not a Chi-Sq problem. It is a 2-sample Z or T test problem.
\n" ); document.write( "---
\n" ); document.write( "Also, a strict rule for hypothesist testing requires that
\n" ); document.write( "equality ALWAYS appears in the Null Hypothesis.
\n" ); document.write( "----
\n" ); document.write( "I think if you use Google you will be able to find examples
\n" ); document.write( "online of a 2-Sample test.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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