document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=522994>Question 522994</A>: <I><SPAN STYLE=\"word-break: break-all;\"> P=6000,R=6%,t=3 then the interest is compound yearly<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347141 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347141\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Principal P =	6000							<BR>\n" );
document.write( "Amount=	A							<BR>\n" );
document.write( "years=n	3.00							<BR>\n" );
document.write( "compounded	1	times a year		t				<BR>\n" );
document.write( "Rate =	6.00			0.06				<BR>\n" );
document.write( "Amount =	P*((n+r)/n)^n*t							<BR>\n" );
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document.write( "Amount =	=	6000	*(	1	+	0.06	)^	3<BR>\n" );
document.write( "Amount =	6000	*(	1	+	0.06	)^	3	<BR>\n" );
document.write( "	6000	*(	1.06	)^	3			<BR>\n" );
document.write( "Amount =	7146.1							\r<BR>\n" );
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document.write( "Amount - Principal = interest </SPAN>\n" );
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