document.write( "Question 522898: The perimeter of a right triangle is 50cm and one of the lengths is 10cm. How do I find the other side and the length of the hypotenuse with this information?\r
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document.write( "P = a + b + c
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document.write( "(c)squared = (a)squared + (b)squared\r
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document.write( "a = 10cm
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document.write( "b = ?
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document.write( "c = ? \n" );
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Algebra.Com's Answer #347137 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Perimeter =50 \n" ); document.write( "one side = 10 \n" ); document.write( "The sum of other 2 sides = 40\r \n" ); document.write( "\n" ); document.write( "let one side be x \n" ); document.write( "other side = 40-x\r \n" ); document.write( "\n" ); document.write( "10^2+(40-x)^2=x^2 \n" ); document.write( "100+1600-80x+x^2=x^2\r \n" ); document.write( "\n" ); document.write( "1700=80x \n" ); document.write( "1700/80=x \n" ); document.write( "x=21.25\r \n" ); document.write( "\n" ); document.write( "40-21.25=18.75\r \n" ); document.write( "\n" ); document.write( "The sides are 10, 18.75,21.25 cm\r \n" ); document.write( "\n" ); document.write( "The longest side is always the hypotenuse\r \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "10^2+18.75^2=451.56 \n" ); document.write( "21.25^2=451.56\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |