document.write( "Question 522954: you invested $29,000 in two accounts paying 8% and 9% annual interest respectively. if the total interest earned for the year was $2350 how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #347117 by Maths68(1474)\"\" \"About 
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\n" ); document.write( "Amount invested at 8% = x
\n" ); document.write( "Amount invested at 9% = 29000-x
\n" ); document.write( "Given
\n" ); document.write( "Total interest on both investments = 2350
\n" ); document.write( "8% * (x) + 9% * (29000-x) = 2350
\n" ); document.write( "8/100 * (x) + 9/100 * (29000-x) = 2350
\n" ); document.write( "8/100 * (x) + 9/100 * (29000-x) = 2350
\n" ); document.write( "Multiply by 100 both sides
\n" ); document.write( "8 * (x) + 9 * (29000-x) = 2350 * 100
\n" ); document.write( "8x + 261000-9x = 235000
\n" ); document.write( "-x=235000-261000
\n" ); document.write( "-x=-26000
\n" ); document.write( "Multiply by -1 boths sides
\n" ); document.write( "x=26000
\n" ); document.write( "Amount invested at 8% = x =26000
\n" ); document.write( "Amount invested at 9% =29000-x=29000-26000 = 3000 \r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "=====
\n" ); document.write( "26000 * 8/100 +3000 * 9/100 = 2350
\n" ); document.write( "260*8+30*9=2350
\n" ); document.write( "2080+270=2350
\n" ); document.write( "2350=2350
\n" ); document.write( " \n" ); document.write( "
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