document.write( "Question 522945: 3. A sample of consumers was surveyed regarding their visits to a computer chain store and if the store was conveniently located. The following table summarizes the results of that survey:
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document.write( "Visits Convenient Not Convenient Totals
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document.write( " Often 60 20 80
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document.write( " Occasional 25 35 60
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document.write( " Never 5 50 55
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document.write( "Column Totals 90 105 195\r
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document.write( "a. What is this table called
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document.write( "b. Are frequency of visits and convenience independent or related? Explain your answer. What is the probability of a survey respondent being convenient to a store?
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document.write( "c. What is the probability of a survey respondent being not convenient to a store and never visiting a store in the chain?
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Algebra.Com's Answer #347111 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A sample of consumers was surveyed regarding their visits to a computer chain store and if the store was conveniently located. The following table summarizes the results of that survey: \n" ); document.write( " \n" ); document.write( "Visits Convenient Not Convenient Totals \n" ); document.write( " Often 60 20 80 \n" ); document.write( " Occasional 25 35 60 \n" ); document.write( " Never 5 50 55 \n" ); document.write( "Column Totals 90 105 195\r \n" ); document.write( "\n" ); document.write( "a. What is this table called: A contingency table. \n" ); document.write( "------------------------------- \n" ); document.write( "b. Are frequency of visits and convenience independent or related? Explain your answer. \n" ); document.write( "P(often) = 80/195 ; P(convenient) = 90/195 \n" ); document.write( "P(often)*P(confenient) = 0.1893 \n" ); document.write( "P(often | convenient) = 60/90 = 2/3 \n" ); document.write( "Since P(oft | conven) is not equal to P(oft)*P(conven) \n" ); document.write( "they are dependent factors. \n" ); document.write( "-------------------------------------------------------------- \n" ); document.write( " \n" ); document.write( "What is the probability of a survey respondent being convenient to a store? \n" ); document.write( "P(convenient+ = 90/195 \n" ); document.write( "----------------------------- \n" ); document.write( "c. What is the probability of a survey respondent being not convenient to a store and never visiting a store in the chain? \n" ); document.write( "P(not convenient AND never visiting) = P(con | never)*P(never) \n" ); document.write( "= 5/55 * 55/195 = 5/195 \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================================ \n" ); document.write( " \n" ); document.write( " |