document.write( "Question 52051: To whom may it concern,\r
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document.write( "I couldn't solve this problem. Please help.\r
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document.write( "Question\r
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document.write( "Steven left Town A and walked towards Town B at a speed of 100 m/min. At the same time, Jason and Melvin started from Town B and walked towards Town A at a speed of 80 m/min and 75 m/min respectively. If Steven met Melvin six minutes after passing Jason, find the distance between Town A and Town B.\r
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document.write( "Thank you very much.\r
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document.write( "CH Lam. \n" );
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Algebra.Com's Answer #34710 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Question \n" ); document.write( "Steven left Town A and walked towards Town B at a speed of 100 m/min. At the same time, Jason and Melvin started from Town B and walked towards Town A at a speed of 80 m/min and 75 m/min respectively. \n" ); document.write( "RELATIVE SPEED OF STEVEN AND JASON = 100+80 = 180 M/MT. \n" ); document.write( "RELATIVE SPEED OF STEVEN AND MELVIN = 100+75=175 M/MT. \n" ); document.write( "If Steven met Melvin six minutes after passing Jason, find the distance between Town A and Town B. \n" ); document.write( "LET DISTANCE BETWEEN A AND B = D \n" ); document.write( "STEVEN MEETS JASON IN = D/180 MT \n" ); document.write( "STEVEN MEETS MELVIN IN =D/175 MTS \n" ); document.write( "DIFFERENCE = D/175 - D/180 =5D/(180*175) MTS.= 6 MTS. \n" ); document.write( "D = 6*180*175/5=6*180*35=37800 M. =37.8 KM\r \n" ); document.write( "\n" ); document.write( "Thank you very much. \n" ); document.write( " \n" ); document.write( " |