document.write( "Question 52051: To whom may it concern,\r
\n" ); document.write( "\n" ); document.write( "I couldn't solve this problem. Please help.\r
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\n" ); document.write( "\n" ); document.write( "Steven left Town A and walked towards Town B at a speed of 100 m/min. At the same time, Jason and Melvin started from Town B and walked towards Town A at a speed of 80 m/min and 75 m/min respectively. If Steven met Melvin six minutes after passing Jason, find the distance between Town A and Town B.\r
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\n" ); document.write( "\n" ); document.write( "CH Lam.
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Algebra.Com's Answer #34710 by venugopalramana(3286)\"\" \"About 
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Question
\n" ); document.write( "Steven left Town A and walked towards Town B at a speed of 100 m/min. At the same time, Jason and Melvin started from Town B and walked towards Town A at a speed of 80 m/min and 75 m/min respectively.
\n" ); document.write( "RELATIVE SPEED OF STEVEN AND JASON = 100+80 = 180 M/MT.
\n" ); document.write( "RELATIVE SPEED OF STEVEN AND MELVIN = 100+75=175 M/MT.
\n" ); document.write( "If Steven met Melvin six minutes after passing Jason, find the distance between Town A and Town B.
\n" ); document.write( "LET DISTANCE BETWEEN A AND B = D
\n" ); document.write( "STEVEN MEETS JASON IN = D/180 MT
\n" ); document.write( "STEVEN MEETS MELVIN IN =D/175 MTS
\n" ); document.write( "DIFFERENCE = D/175 - D/180 =5D/(180*175) MTS.= 6 MTS.
\n" ); document.write( "D = 6*180*175/5=6*180*35=37800 M. =37.8 KM\r
\n" ); document.write( "\n" ); document.write( "Thank you very much.
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