document.write( "Question 6420: can you solve these problems in step?\r
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document.write( "Set2\r
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document.write( "1. Solve the equation 5x+3y=-15, for x if y=0.\r
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document.write( "2. find the x- intercept for the equation 6x-y= -12\r
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document.write( "3. determine the equation of the line with slope -3 and containing (-7,2)\r
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document.write( "4. given the following , write an equation in standard form. The line has y-intercept 5 and slope 2\r
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document.write( "5. write an equation of the line in slope- intercept form if contains (-1,2) and ( 5, -4)\r
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document.write( "6. write an equation slope intercept form of the line that is parallel to the graph of 3y-4x=1 and passes through (0,6)\r
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document.write( "7. write the equation in standard form for the line that is perpendicular to the graph of y=5x+1 and has a y-intercept of 4.\r
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document.write( "8. write the equation of the vertical line that contains (-5,-4).\r
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document.write( "9. find the slope for the equation x-2y=6\r
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document.write( "10. for the equation x-2y=6, is the point (4,-1) on the line?
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Algebra.Com's Answer #3471 by sabanasir(22)![]() ![]() ![]() You can put this solution on YOUR website! Solutions: \n" ); document.write( "1) 5x + 3y =15 \n" ); document.write( " when y = 0 \n" ); document.write( " 5x + 3(0) =15 \n" ); document.write( " 5x = 15 \n" ); document.write( " x = 3 \n" ); document.write( "3) slope = -3 and (x,y) = (-7,2) \n" ); document.write( " we use the equation formula: \n" ); document.write( " m= (y-y1) / (x - x1) \n" ); document.write( " m is slope and (x1,y1) = (-7,2) \n" ); document.write( " so, \n" ); document.write( " -3 = ( y - 2 ) / ( x + 7 ) \n" ); document.write( " -3 ( x + 7 ) = y - 2 \n" ); document.write( " -3x - 21 = y - 2 \n" ); document.write( " 3x + y - 2 + 21 = 0 \n" ); document.write( " 3x + y + 20 = 0 \n" ); document.write( "5) consider (x1,y1) = (-1,2) and (x2,y2) = ( 5,-4) \n" ); document.write( " slope is m \n" ); document.write( " m = (y2-y1)/(x2-x1) \n" ); document.write( " m = (-4 -2) / ( 5 + 1) \n" ); document.write( " m = -6/ 6 \n" ); document.write( " m = -1 \n" ); document.write( " considering any point as (x1,y1) \n" ); document.write( " here we take (x1,y1) = (-1,2) \n" ); document.write( "using \n" ); document.write( " m = (y - y1) / ( x - x1) \n" ); document.write( " putting m = -1 \n" ); document.write( " -1 = ( y - 2 )/ ( x + 1) \n" ); document.write( " -x - 1 = y - 2 \n" ); document.write( " x + y -2 + 1 = 0 \n" ); document.write( " x + y -1 = 0 \n" ); document.write( "6) for parallel line slope is the same. so is we take out 3y - 4x =1 's slope it would be useed for the point ( 0 , 6) also. \n" ); document.write( " FINDING SLOPE: \n" ); document.write( " 3y - 4x = 1 \n" ); document.write( " y = ( 4x +1 ) / 3 \n" ); document.write( " y = 4x/3 + 1/3 \n" ); document.write( " comparing with y=mx+c \n" ); document.write( " we get m = 4/3 \n" ); document.write( " now putting it in m = (y - y1) / ( x - x1) \n" ); document.write( " where m = 4/3, (x1,y1) = ( 0 , 6 ) \n" ); document.write( " we get: \n" ); document.write( " 4/3 = ( y - 6 ) / ( x - 0 ) \n" ); document.write( " 4 = (3y - 18) / x \n" ); document.write( " 4x = 3y - 18 \n" ); document.write( " 4x - 3y =18 ANSWER. \n" ); document.write( " 9) y = mx + c \n" ); document.write( " here c is constant \n" ); document.write( " x-2y = 6 \n" ); document.write( " y = -(- x + 6) / 2 \n" ); document.write( " y = x/2 - 6/2 \n" ); document.write( " y = x/2 - 3 \n" ); document.write( " comparing with y = mx+c and m is slope \n" ); document.write( " here, \n" ); document.write( " m = 1/2. \n" ); document.write( " \n" ); document.write( " |