document.write( "Question 522747: Dear Tutor,\r
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document.write( "I am having a hard time trying to work out this problem. Would you please be so kind as to try and help me.\r
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document.write( "This is the question:
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document.write( "John is 3 times younger than his dad's age. The sum of their ages is 79. Find Johns age as a fraction.\r
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document.write( "I tied by saying 79 divide by 3 and got 26 and a third but I would like to know for sure.\r
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document.write( "Thank you for taking the time to help me\r
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document.write( "kind regards
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document.write( "Tracey \n" );
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Algebra.Com's Answer #347091 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! I would do it this way \n" ); document.write( ": \n" ); document.write( "John is 3 times younger than his dad's age. \n" ); document.write( "d = 3j \n" ); document.write( "but they want John's age as a fraction, divide both sides by 3 \n" ); document.write( "j = \n" ); document.write( ": \n" ); document.write( "The sum of their ages is 79. \n" ); document.write( "d + j = 79 \n" ); document.write( ": \n" ); document.write( "replace j with \n" ); document.write( "1d + \n" ); document.write( ": \n" ); document.write( "1 1/3 = 4/3, so write it \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "multiply both sides by 3, to get rid of the denominators \n" ); document.write( "4d = 3(79) \n" ); document.write( "4d = 237 \n" ); document.write( "d = 237/4 \n" ); document.write( "d = 59.25 is Dad's age \n" ); document.write( "then \n" ); document.write( "j = \n" ); document.write( "j = 19.75 or 19 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the sum of their ages \n" ); document.write( "59.25 \n" ); document.write( "19.75 \n" ); document.write( "----- \n" ); document.write( "79.00 \n" ); document.write( " |