document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=522932>Question 522932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A plane leaves an airport and flies south at 184 mph. later, a second plane leaves the same airport and flies south at 460mph. If the second plane overtakes the first one in 1 1/2 hours, how long of a head start did the first plane have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #347080 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=347080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d = r*t is the basic distance equation.<BR>\n" );
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document.write( "The first plane flies for 1 1/2 = 3/2 hr at 184 mph.<BR>\n" );
document.write( "d = 3/2 * 184 = 3 * 92 = 276 miles<BR>\n" );
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document.write( "The second also flies 276 miles to overtake the first plane<BR>\n" );
document.write( "It does this at a rate of 460 mph.<BR>\n" );
document.write( "So, it flies for a different amount of time.<BR>\n" );
document.write( "t = d/r<BR>\n" );
document.write( "t = 276/460 = 3/5 hr * 60 min/hr = 36 min <BR>\n" );
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document.write( "The first plane flies for 3/2 hr * 60 min/hr = 90 min<BR>\n" );
document.write( "So its head start was 90-36 = 54 minutes.<BR>\n" );
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document.write( "Done.  </SPAN>\n" );
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