document.write( "Question 52050: I have the problem with this question. Please help.\r
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document.write( "A passenger train travelled at a speed of 72 km/h. A man on the passenger train observed a goods train travelling at a speed of 54 km/h in the opposite direction. If the goods train passed him in 8 seconds, find the length of the good train. (Hint : Model the problem and draw a diagram).\r
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document.write( "Thank you in anticipation.\r
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document.write( "CH Lam \n" );
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Algebra.Com's Answer #34708 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! A passenger train travelled at a speed of 72 km/h. \r \n" ); document.write( "\n" ); document.write( "A man on the passenger train observed a goods train travelling at a speed of 54 km/h in the opposite direction. \n" ); document.write( "RELATIVE SPEED OF 2 TRAINS TRAVELLING OPPOSITE TO EACH OTHER = 72+54 \n" ); document.write( "=126 KMPH..=126000/3600 M/SEC=1260/36=210/6=35 M/SEC \n" ); document.write( "IF YOU DO NOT UNDERSTAND THIS CONCEPT REFER MY EARLIER SOLUTIONS ON THIS TOPIC OR PLEASE COME BACK. \n" ); document.write( " If the goods train passed him in 8 seconds, find the length of the good train. \n" ); document.write( "GOODS TRAIN PASSES MEANS FROM THE TIME PASSENGER SEES ITS FIRST BOGIE (SAY ENGINE) TO THE TIME HE SEES ITS LAST BOGIE..THAT IS A DISTANCE TRAVELLED EQUAL TO LENGTH OF GOODS TRAIN = L SAY \n" ); document.write( "TIME = 6SEC. \n" ); document.write( "L=35 *6 = 210 M.\r \n" ); document.write( "\n" ); document.write( "(Hint : Model the problem and draw a diagram). NO NEED TO MODEL!!! \n" ); document.write( "Thank you in anticipation. \n" ); document.write( " |