document.write( "Question 522870: the sum of two numbers is 18. if twice the smaller number is 6 more than the larger, find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #347056 by umail08(87)\"\" \"About 
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Let x = smaller number
\n" ); document.write( "Let y = larger number\r
\n" ); document.write( "\n" ); document.write( "x + y = 18 ... represents the sum of two numbers\r
\n" ); document.write( "\n" ); document.write( "2x = y + 6 .... twice smaller is 6 more than the larger\r
\n" ); document.write( "\n" ); document.write( "Solve using system of equations:\r
\n" ); document.write( "\n" ); document.write( "1) x + y = 18
\n" ); document.write( "2) 2x = y + 6\r
\n" ); document.write( "\n" ); document.write( "1) x + y = 18
\n" ); document.write( "2) 2x - y = 6 \r
\n" ); document.write( "\n" ); document.write( " 3x = 24 ... add the two equations ... the y variables cancel out...
\n" ); document.write( " 3x/3 = 24/3
\n" ); document.write( " x = 8 ... smaller number\r
\n" ); document.write( "\n" ); document.write( "1) x + y = 18
\n" ); document.write( " 8 + y = 18
\n" ); document.write( " y = 18 - 8
\n" ); document.write( " y = 10 .... larger number
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