document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52050>Question 52050</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have the problem with this question. Please help.\r<BR>\n" );
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document.write( "A passenger train travelled at a speed of 72 km/h. A man on the passenger train observed a goods train travelling at a speed of 54 km/h in the opposite direction.  If the goods train passed him in 8 seconds, find the length of the good train. (Hint : Model the problem and draw a diagram).\r<BR>\n" );
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document.write( "Thank you in anticipation.\r<BR>\n" );
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document.write( "CH Lam </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34703 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The goods train passes him at the com bined rates of both trains, or<BR>\n" );
document.write( "72 + 45 = 126 km/hr<BR>\n" );
document.write( "If the train passes in 8 sec, the length of the train is (126 km/hr)(8 sec)<BR>\n" );
document.write( "There are 3600 sec in an hour 126 km/3600 sec * 8 sec = 126/450 km<BR>\n" );
document.write( "That equals 126000/450 meters = 280 meters long </SPAN>\n" );
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