document.write( "Question 522806: If x is measured in radians, then the derivative of Sin[x] with respect to x is Cos[x].\r
\n" ); document.write( "\n" ); document.write( "Use the formula Sin [x degrees] = Sin [2π/360 x radians]
\n" ); document.write( "to calculate the derivative of Sin [x degrees] with respect to x.\r
\n" ); document.write( "\n" ); document.write( "Why does the resulting formula make calculus difficult if you insist on working with degrees instead of radians?\r
\n" ); document.write( "\n" ); document.write( "Thanks for any help you can offer!
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Algebra.Com's Answer #347023 by Alan3354(69443)\"\" \"About 
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If x is measured in radians, then the derivative of Sin[x] with respect to x is Cos[x].\r
\n" ); document.write( "\n" ); document.write( "Use the formula Sin [x degrees] = Sin [2π/360 x radians]
\n" ); document.write( "to calculate the derivative of Sin [x degrees] with respect to x.
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\n" ); document.write( "f(x) = sin(x), x in degrees
\n" ); document.write( "f(x) = sin(x*180/pi) radians
\n" ); document.write( "f'(x) = cos(x*180/pi)*(180/pi), x in degrees
\n" ); document.write( "f'(x) = (180/pi)*cos(x), x in radians
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\n" ); document.write( "Why does the resulting formula make calculus difficult if you insist on working with degrees instead of radians?
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\n" ); document.write( "It's more complicated because x is multiplied by a constant, (180/pi).
\n" ); document.write( "Degrees are \"artificial\" or arbitrary units, the same as gradients.
\n" ); document.write( "Radians are a function of the ratio of the arc length to the radius, so the units of the circle, cm, feet, miles, whatever, are canceled. Radians are \"unitless\" measure.
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