document.write( "Question 522686: If a train travels at the speed of 45 km/hr, it is late by 48 minutes. If it travels 50 km/hr it arrives exactly on time. What is distance the train is traveling (in km)? \n" ); document.write( "

Algebra.Com's Answer #347018 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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If a train travels at the speed of 45 km/hr, it is late by 48 minutes.
\n" ); document.write( " If it travels 50 km/hr it arrives exactly on time.
\n" ); document.write( " What is distance the train is traveling (in km)?
\n" ); document.write( ":
\n" ); document.write( "let d = the distance traveled
\n" ); document.write( "then
\n" ); document.write( " $\"d%2F50\"$ = the time to arrive on time
\n" ); document.write( "and
\n" ); document.write( " $\"d%2F45\"$ = the time to be 48 min late
\n" ); document.write( ":
\n" ); document.write( "Convert 48 min: $\"48%2F60\"$ = .8hrs
\n" ); document.write( ":
\n" ); document.write( "slower time - ideal time = .8 hrs
\n" ); document.write( " $\"d%2F45\"$ - $\"d%2F50\"$ = .8
\n" ); document.write( "multiply by 450
\n" ); document.write( "450* $\"d%2F45\"$ - 450* $\"d%2F50\"$ = 450(.8)
\n" ); document.write( "cancel the denominators, results:
\n" ); document.write( "10d - 9d = 360
\n" ); document.write( "d = 360 miles is the distance
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the times
\n" ); document.write( "360/45 = 8.0 hrs, late
\n" ); document.write( "360/50 = 7.2 hrs. on time
\n" ); document.write( "-----------------
\n" ); document.write( "differs: .8 hrs which is 48 min \n" ); document.write( "

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