document.write( "Question 52028: please help me solve \"%28x%2B3%29%2F2+=+3+\" (x plus three over two equals three)
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Algebra.Com's Answer #34701 by AnlytcPhil(1806)\"\" \"About 
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document.write( "                 x + 3\r\n" );
document.write( "               -------- = 3\r\n" );
document.write( "                   2\r\n" );
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document.write( "Put the 3 over 1 so everything will be fractions:\r\n" );
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document.write( "                 x + 3     3\r\n" );
document.write( "               -------- = ---\r\n" );
document.write( "                   2       1\r\n" );
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document.write( "The LCD of 2 and 1 is 2.  So multiply both sides by\r\n" );
document.write( "2 over 1:\r\n" );
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document.write( "          2     x + 3      2     3\r\n" );
document.write( "         --- · -------- = --- · ---\r\n" );
document.write( "          1       2        1     1\r\n" );
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document.write( "We cancel the 2's on the left and multiply the \r\n" );
document.write( "numerators 2·3, getting 6, and denominators 1·1, \r\n" );
document.write( "getting 1 on the right:\r\n" );
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document.write( "          1\r\n" );
document.write( "          2     x + 3      6     \r\n" );
document.write( "         --- · -------- = --- \r\n" );
document.write( "          1       2        1     \r\n" );
document.write( "                  1\r\n" );
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document.write( "So we can ignore the 1's on the bottome and just have\r\n" );
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document.write( "                  x + 3 = 6      \r\n" );
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document.write( "which you should have no trouble solving.\r\n" );
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document.write( "Edwin\r\n" );
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