document.write( "Question 522706: Students took an Algebra 2/Trig Test with a mean of 87.5% with a standard deviation of 4.5%.
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document.write( "What is the probability that a student scored between 84 and 100%? \n" );
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Algebra.Com's Answer #346993 by stanbon(75887) ![]() You can put this solution on YOUR website! Students took an Algebra 2/Trig Test with a mean of 87.5% with a standard deviation of 4.5%. \n" ); document.write( "What is the probability that a student scored between 84 and 100%? \n" ); document.write( "-------------- \n" ); document.write( "z(84) = (84-87.5)/4.5 = -0.7778 \n" ); document.write( "--- \n" ); document.write( "z(100) = (100-87.5)/4.5 = 2.7778 \n" ); document.write( "---- \n" ); document.write( "P(84 <= x <=100) = P(-0.7778 <= z <= 2.778) = 0.7789 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |