document.write( "Question 522770: What is the area of an isosceles triangle with the base angles of 57degrees and a base of 15 \n" ); document.write( "
Algebra.Com's Answer #346988 by stanbon(75887)\"\" \"About 
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What is the area of an isosceles triangle with the base angles of 57degrees and a base of 15
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\n" ); document.write( "Sketch the triangle with base 15 and base angles 57 degrees.
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\n" ); document.write( "Draw a perpendicular bisector of the base.
\n" ); document.write( "That bisector is the altitute of the triangle.
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\n" ); document.write( "You have a right triangle on the right side
\n" ); document.write( "with base = 15/2 = 7.5
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\n" ); document.write( "Solve tan(57) = alt/7.5
\n" ); document.write( "altitude = 7.5*tan(57) = 11.55
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\n" ); document.write( "Area = (1/2)base*altitude
\n" ); document.write( "A = (1/2)*7.5*11.55 = 43.31 sq units
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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