document.write( "Question 522662: I just submitted a question concerning spreading gravel in my driveway. I inadvertently asked how many \"square yards\" of gravel it would take instead of asking how many \"CUBIC yards\" it would take!! I am spreading gravel 3 inches deep, 12 feet wide and 900 feet long. I MAY decide to spread it 4 inches deep instead. I need to know how many CUBIC yards of material would be required in either scenario. What formula would I employ? \n" ); document.write( "
Algebra.Com's Answer #346977 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
I am spreading gravel 3 inches deep, 12 feet wide and 900 feet long. I MAY decide to spread it 4 inches deep instead.
\n" ); document.write( " I need to know how many CUBIC yards of material would be required in either scenario.
\n" ); document.write( ":
\n" ); document.write( "Change 3 in to .25 ft
\n" ); document.write( "Find the vol in cu/ft; .25*12*900 = 2700 cu/ft
\n" ); document.write( "Change 2700 cu/ft to cu yds: 2700.27 = 100 cu yds for 3\" thickness
\n" ); document.write( ":
\n" ); document.write( "Change 4 in to \"1%2F3\" ft
\n" ); document.write( "Find the vol: (1/3)*12*900 = 3600 cu/ft
\n" ); document.write( "Change 3600 cu/ft to cu yds: 3600/27 = 133\"1%2F3\" cu yds for 4\" thickness
\n" ); document.write( "
\n" );