document.write( "Question 522689: David is traveling to the airport to catch a flight, if he travels at the speed of 30 mph, he is late by 13 minutes. If he travels at the speed of 40 mph, he will arrive 7 minutes earlier than the scheduled departure time of the flight. What is the distance to the airport (in miles)? \n" ); document.write( "
Algebra.Com's Answer #346973 by ankor@dixie-net.com(22740)\"\" \"About 
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David is traveling to the airport to catch a flight, if he travels at the speed of 30 mph, he is late by 13 minutes.
\n" ); document.write( " If he travels at the speed of 40 mph, he will arrive 7 minutes earlier than the scheduled departure time of the flight.
\n" ); document.write( " What is the distance to the airport (in miles)?
\n" ); document.write( ":
\n" ); document.write( "Let d = distance to airport
\n" ); document.write( "Let s = speed required to arrive on time
\n" ); document.write( "then
\n" ); document.write( "\"d%2Fs\" = the ideal time to the airport
\n" ); document.write( ":
\n" ); document.write( "Write a time equation for each scenario
\n" ); document.write( ":
\n" ); document.write( " \"d%2F30\" - \"d%2Fs\" = \"13%2F60\"; late
\n" ); document.write( "-\"d%2F40\" + \"d%2Fs\" = \"7%2F60\"; early
\n" ); document.write( "--------------------------------------- addition, eliminates d/s
\n" ); document.write( "\"d%2F30\" - \"d%2F40\" + 0 = \"20%2F60\"
\n" ); document.write( "Clear denominators, multiply by 120, results:
\n" ); document.write( "4d - 3d = 2(20)
\n" ); document.write( "d = 40 mi to the airport
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if this works; find s
\n" ); document.write( " \"40%2F30\" - \"40%2Fs\" = \"13%2F60\";
\n" ); document.write( "mult by 60s, results
\n" ); document.write( "2s(40) - 60(40) = 13s
\n" ); document.write( "80s - 2400 = 13s
\n" ); document.write( "80s - 13s = 240
\n" ); document.write( "67s = 2400
\n" ); document.write( "s = \"2400%2F67\"
\n" ); document.write( "s = 35.82 mph the ideal speed
\n" ); document.write( ":
\n" ); document.write( "Check solution in the late equation
\n" ); document.write( "\"40%2F30\" - \"40%2F35.82\" =
\n" ); document.write( "1.3333 - 1.1167 = .2166 hr which is 13 min
\n" ); document.write( "
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