document.write( "Question 522658: There were 510 people at a play. The admission price was $3.00 for adults and $1.00 for children. The admission receits were $930. How many adults and children attended. \n" ); document.write( "
Algebra.Com's Answer #346938 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Adult x Tickets
\n" ); document.write( "child y Tickets
\n" ); document.write( "
\n" ); document.write( "1 x + 1 y = 510 .............1
\n" ); document.write( "3 x + 1 y = 930 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -1
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-1 x -1 y = -510
\n" ); document.write( "3 x 1 y = 930
\n" ); document.write( "Add the two equations
\n" ); document.write( "2 x = 420
\n" ); document.write( "/ 2
\n" ); document.write( "x = 210
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1 x + 1 y = 510
\n" ); document.write( "210 + 1 y = 510
\n" ); document.write( " 1 y = 510 -210
\n" ); document.write( " 1 y = 300
\n" ); document.write( " y = 300
\n" ); document.write( "Adult 210 Tickets
\n" ); document.write( "child 300 Tickets
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
\n" ); document.write( "
\n" );