document.write( "Question 522658: There were 510 people at a play. The admission price was $3.00 for adults and $1.00 for children. The admission receits were $930. How many adults and children attended. \n" ); document.write( "
Algebra.Com's Answer #346938 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Adult x Tickets \n" ); document.write( "child y Tickets \n" ); document.write( " \n" ); document.write( "1 x + 1 y = 510 .............1 \n" ); document.write( "3 x + 1 y = 930 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -1 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "-1 x -1 y = -510 \n" ); document.write( "3 x 1 y = 930 \n" ); document.write( "Add the two equations \n" ); document.write( "2 x = 420 \n" ); document.write( "/ 2 \n" ); document.write( "x = 210 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1 x + 1 y = 510 \n" ); document.write( "210 + 1 y = 510 \n" ); document.write( " 1 y = 510 -210 \n" ); document.write( " 1 y = 300 \n" ); document.write( " y = 300 \n" ); document.write( "Adult 210 Tickets \n" ); document.write( "child 300 Tickets \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |