document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52024>Question 52024</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I have to find the vertex and axis of symmetry of the parabola <BR>\n" );
document.write( "y= -x^2+6x+3 <BR>\n" );
document.write( "I also have to find if it opens upward or downward.  I have done this so far:<BR>\n" );
document.write( "a= -1  b=6 c=3<BR>\n" );
document.write( "Vertex occurs when x= -b\2a  =  -6\2(-1) = 3\r<BR>\n" );
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document.write( "Then y=f(3)= -1(3)^2+6(3)+3<BR>\n" );
document.write( "=12\r<BR>\n" );
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document.write( "Vertex (3,12).<BR>\n" );
document.write( "It is downward because a<0\r<BR>\n" );
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document.write( "I am not sure on the axis of symmetry and how to work it out.<BR>\n" );
document.write( "greatly appreciated if you could please help\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34693 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You had two small errors that were just typos, since your result came out right.  The axis of symmetry is the vertical line x= 3, and the graph is like this:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph+%28300%2C600%2C-10%2C10%2C+-20%2C20%2C+-x%5E2%2B6x%2B3%29+ ALIGN=MIDDLE  ALT=\"graph+%28300%2C600%2C-10%2C10%2C+-20%2C20%2C+-x%5E2%2B6x%2B3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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