document.write( "Question 522553: the shorter leg of a right triangle is 7cm less than the other leg. what is the length of the two legs if the hypotenuse is 35 cm? \n" ); document.write( "
Algebra.Com's Answer #346911 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Hypotenuse = 35 \n" ); document.write( "one leg x \n" ); document.write( "other leg = x-7\r \n" ); document.write( "\n" ); document.write( "Use Pythagoras theorem\r \n" ); document.write( "\n" ); document.write( "x^2+(x-7)^2=35^2\r \n" ); document.write( "\n" ); document.write( "x^2+x^2-14x+49=1225\r \n" ); document.write( "\n" ); document.write( "2x^2-14x-1176=0 \n" ); document.write( "/2 \n" ); document.write( "x^2-7x-588=0\r \n" ); document.write( "\n" ); document.write( "x^2-28x+21x-588=0 \n" ); document.write( "x(x-28)+21(x-28)=0 \n" ); document.write( "(x-28)(x+21)=0 \n" ); document.write( "take the positive value x=28 one leg \n" ); document.write( "other leg = 21\r \n" ); document.write( "\n" ); document.write( "21^2+28^2=1225\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |