document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=522553>Question 522553</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the shorter leg of a right triangle is 7cm less than the other leg. what is the length of the two legs if the hypotenuse is 35 cm? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346911 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hypotenuse = 35<BR>\n" );
document.write( "one leg x<BR>\n" );
document.write( "other leg = x-7\r<BR>\n" );
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document.write( "Use Pythagoras theorem\r<BR>\n" );
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document.write( "x^2+(x-7)^2=35^2\r<BR>\n" );
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document.write( "x^2+x^2-14x+49=1225\r<BR>\n" );
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document.write( "2x^2-14x-1176=0<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "x^2-7x-588=0\r<BR>\n" );
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document.write( "x^2-28x+21x-588=0<BR>\n" );
document.write( "x(x-28)+21(x-28)=0<BR>\n" );
document.write( "(x-28)(x+21)=0<BR>\n" );
document.write( "take the positive value x=28 one leg<BR>\n" );
document.write( "other leg = 21\r<BR>\n" );
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document.write( "21^2+28^2=1225\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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