document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=522515>Question 522515</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Steamer cruises 58 kilometers downstream in the same time that is cruises 40 kilometers  upstream.  The engines drive the steamer in calm water at a rate which is 20 km/hr more than the rate of the current.  Find the rate of the current.\r<BR>\n" );
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document.write( "How do I set this up? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346909 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let current speed = x<BR>\n" );
document.write( "steamer speed = x+20\r<BR>\n" );
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document.write( "upstream speed = (x+20-x)=20 mph<BR>\n" );
document.write( "downstream speed = 2x+20\r<BR>\n" );
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document.write( "upstream distance = 40<BR>\n" );
document.write( "downstream distance = 58\r<BR>\n" );
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document.write( "times are same\r<BR>\n" );
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document.write( "t=d/r\r<BR>\n" );
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document.write( "40/20 = 58/(2x+20)<BR>\n" );
document.write( "cross multiply<BR>\n" );
document.write( "40(2x+20)=58*(20)<BR>\n" );
document.write( "80x+800=1160<BR>\n" );
document.write( "80x=1160-800<BR>\n" );
document.write( "80x=360<BR>\n" );
document.write( "x=4.5 mph\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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