document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=522524>Question 522524</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anabelle runs the same route every day. She runs part of the way and jogs part of the way. She runs at a speed of 6 mph. She jogs at a speed of 4 mph. If her route is 5 miles, and it takes her one hour how far does she jog? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346907 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let her jog x miles<BR>\n" );
document.write( "so she runs 5-x miles\r<BR>\n" );
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document.write( "jog time + run time = 1 hoyr\r<BR>\n" );
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document.write( "t=d/r\r<BR>\n" );
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document.write( "x/4 + (5-x)/6=1\r<BR>\n" );
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document.write( "LCD = 12, multiply by the LCD\r<BR>\n" );
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document.write( "3x+2(5-x)=12<BR>\n" );
document.write( "3x+10-2x=12<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "x=2 <BR>\n" );
document.write( "she jogs for 2 miles\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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