document.write( "Question 522518: Can you please help me with this problem? i have to identify the conic section in standard form then graph. x^2+y^2-4y-5=0 \n" ); document.write( "

Algebra.Com's Answer #346900 by Earlsdon(6294) $\"\"$ $\"About$

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Identify the conic section:
\n" ); document.write( " $\"x%5E2%2By%5E2-4y-5+=+0\"$ Add 5 to both sides.
\n" ); document.write( " $\"x%5E2%2B%28y%5E2-4y%29+=+5\"$ Complete the square in y by adding 4 to both sides.
\n" ); document.write( " $\"x%5E2%2B%28y%5E2-4y%2B4%29+=+5%2B4\"$ Factor the group in y and simplify.
\n" ); document.write( " $\"x%5E2%2B%28y-2%29%5E2+=+9\"$ Compare this with the standard form for a circle of radius r with center at (h, k).
\n" ); document.write( " $\"%28x-h%29%5E2%2B%28y-k%29%5E2+=+r%5E2\"$ and you can see that you have a circle of radius 3 with center at (0,2).
\n" ); document.write( "I forgot the graph:
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