document.write( "Question 522487: The length of a rectangle is 5cm longer than the width. The perimiter is 54 cm. Find the demensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #346872 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! L = W+5 \n" ); document.write( "2(L+W) =54 \n" ); document.write( "substitute \n" ); document.write( "2((W+5) +W) = 54 \n" ); document.write( "W+5+W = 27 \n" ); document.write( "2W = 22 \n" ); document.write( "W = 11 \n" ); document.write( "L = W+5 \n" ); document.write( "L = 16 \n" ); document.write( ". \n" ); document.write( "Check perimeter \n" ); document.write( ". \n" ); document.write( "2(L+W) = 2(27) = 54 \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Answer: Length = 16, Width = 11 \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |