document.write( "Question 522487: The length of a rectangle is 5cm longer than the width. The perimiter is 54 cm. Find the demensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #346872 by oberobic(2304)\"\" \"About 
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L = W+5
\n" ); document.write( "2(L+W) =54
\n" ); document.write( "substitute
\n" ); document.write( "2((W+5) +W) = 54
\n" ); document.write( "W+5+W = 27
\n" ); document.write( "2W = 22
\n" ); document.write( "W = 11
\n" ); document.write( "L = W+5
\n" ); document.write( "L = 16
\n" ); document.write( ".
\n" ); document.write( "Check perimeter
\n" ); document.write( ".
\n" ); document.write( "2(L+W) = 2(27) = 54
\n" ); document.write( "Correct.
\n" ); document.write( ".
\n" ); document.write( "Answer: Length = 16, Width = 11
\n" ); document.write( ".
\n" ); document.write( "Done.
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