document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51987>Question 51987</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have the following problem; rewrite this equation as a funtion of x; the eqaution is -3x + 4 = 11. If I'm doing this right I get as far as y = -3x + 11 and then I get competely lost, could you please explain the next step to me. I know I'm forgetting an operation, but can't remember what. Thank You. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34686 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3X+4=11 OR subtracting 4 from both sides we get -3X+4-4=11-4 OR -3x=11-4 OR<BR>\n" );
document.write( "-3X=7 OR dividing both sides by -3 we get -3X/-3=7/-3 OR X=7/-3 OR x=-7/3 \r<BR>\n" );
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document.write( "PROOF -3(-7/3)+4=11 OR 7+4=11 OR 11=11 </SPAN>\n" );
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