document.write( "Question 522423: Beth is four more than three times older than Ted. The sum of their ages is 60. How old is Ted? \n" ); document.write( "
Algebra.Com's Answer #346853 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Beth is four more than three times older than Ted. The sum of their ages is 60. How old is Ted? \n" ); document.write( "======================= \n" ); document.write( "3 times older is 4 times as old. \n" ); document.write( "B = Beth's age, T = Ted's age \n" ); document.write( "B = 4T + 3 \n" ); document.write( "B + T = 60 \n" ); document.write( "(4T+3) + T = 60 \n" ); document.write( "5T + 3 = 60 \n" ); document.write( "T = 57/5 = 11.4 \n" ); document.write( "--------------------- \n" ); document.write( "The author of this problem thinks 3 times older is the same as 3 times as old. \n" ); document.write( "If that's true, what is 1 time older? The same age? If so, why is it called older? \n" ); document.write( "----------- \n" ); document.write( "Don't even mention \"100 times thinner.\" 1 times thinner is zero, so how can something be 100 times thinner, or 10 times closer. \n" ); document.write( "English, learn it. \n" ); document.write( "It's a bad problem, no integer solution. \n" ); document.write( " |