document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=522401>Question 522401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to set this problem up\r<BR>\n" );
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document.write( "The lenghth of a rectangle is six cm more than one and one-half times the width.The perimeter of the rectangle if fifty-six cm.find the dimensions.\r<BR>\n" );
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document.write( "I put l=6+1and1/2<BR>\n" );
document.write( "56=2w+2l<BR>\n" );
document.write( "I don't think that's right though </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346846 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is six cm more than one and one-half times the width.The perimeter of the rectangle if fifty-six cm.find the dimensions. <BR>\n" );
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document.write( "Let width be \"W\":<BR>\n" );
document.write( "Then L = (3/2)W + 6<BR>\n" );
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document.write( "Perimeter = 2(L + W)<BR>\n" );
document.write( "56 = 2((3/2)W+6 + W)<BR>\n" );
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document.write( "28 = (5/2)W + 6<BR>\n" );
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document.write( "(5/2)W = 22<BR>\n" );
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document.write( "Width = (2/5)(22) = 44/5 = 8.8 cm<BR>\n" );
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document.write( "Lenght = (3/2)(8.8) + 6 = 19.2 cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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