document.write( "Question 522392: Find the area of a rectangle whose length is 6 inches less than 5 times the width and whose perimeter is 8 inches more than twice the length. \n" ); document.write( "
Algebra.Com's Answer #346819 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is twice the length plus twice the width. So if the perimeter is twice the length plus 8, twice the width has to be 8. Width = 4 and you can calculate the length for yourself.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |