document.write( "Question 522289: Factor completely:\r
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document.write( "40y^4 - 5y\r
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document.write( "I just know how to simplify.. but I do not know where to go from there...
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document.write( "5y(8y^3 - 1) \n" );
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Algebra.Com's Answer #346773 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 5y(8y^3 - 1) \n" ); document.write( "------------ \n" ); document.write( "(8y^3 - 1) is a difference of 2 cubes, (2y)^3 - 1^3 \n" ); document.write( "---------- \n" ); document.write( "The difference of 2 cubes a^3 - b^3 = (a-b)*(a^2 + ab + b^2) \n" ); document.write( " \n" ); document.write( " |