document.write( "Question 522219: Hi, this has me stumped:
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document.write( "Two drivers 240 miles apart start toward each other at 2pm. The faster one averages 50 mph and the slower one averages 35mph. The faster one stops for 2 hours along the way before they pass each other. \r
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document.write( "Write the equation to determine how long it will take them before they pass each other.\r
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document.write( " I cant sort out how to express the 2 hours of not traveling... this is what I have so far: 240-35t= 50*(4.8-2.0) \r
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document.write( "Above, I'm not sure if I should be subtracting 2 or adding 2 or if that equation is even right :/ \n" );
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Algebra.Com's Answer #346763 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two drivers 240 miles apart start toward each other at 2pm. \n" ); document.write( " The faster one averages 50 mph and the slower one averages 35mph. \n" ); document.write( " The faster one stops for 2 hours along the way before they pass each other. \n" ); document.write( "Write the equation to determine how long it will take them before they pass each other. \n" ); document.write( ": \n" ); document.write( "Let t = travel time of the slower car \n" ); document.write( "then \n" ); document.write( "(t-2) = travel time of the faster \n" ); document.write( ": \n" ); document.write( "When they do pass each other the sum of their travel distances = 240 \n" ); document.write( "Write a dist equation: dist = speed * time \n" ); document.write( ": \n" ); document.write( "fast car dist + slow car dist = 240 mi \n" ); document.write( "50(t-2) + 35t = 240\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |