document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=522240>Question 522240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving this problem\r<BR>\n" );
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document.write( "Solve the system by back substitution\r<BR>\n" );
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document.write( "3x - 2y - 4z + 2w = 6<BR>\n" );
document.write( "     2y + 5z - 3w = 7<BR>\n" );
document.write( "          3z -4w = 0<BR>\n" );
document.write( "              3w = 15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346745 by </B><A HREF=/tutors/aboutme.mpl?userid=umnikmo><B>umnikmo(75)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=umnikmo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346745\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x - 2y - 4z + 2w = 6 (1)<BR>\n" );
document.write( "2y + 5z - 3w = 7      (2)<BR>\n" );
document.write( "3z -4w = 0            (3)<BR>\n" );
document.write( "3w = 15               (4)\r<BR>\n" );
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document.write( "from (4): w=5<BR>\n" );
document.write( "from (3): z=4w/3=20/3<BR>\n" );
document.write( "from (2): y=(7+3w-5z)/2=(7+3*5-5*20/3)/2=-17/3<BR>\n" );
document.write( "from (1): x=(6-2w+4z+2y)/3=(6-2*5+4*20/3+2*(-17/3))/3=34/9<BR>\n" );
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