document.write( "Question 522149: You need a 40% alcohol solution. On hand, you have a 650 mL of a 20% alcohol mixture. You also have 90% alcohol mixture. How much of the 90% mixture will you need to add to obtain the desired solution?\r
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document.write( "You will need
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document.write( " mL of the 90% solution
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document.write( "to obtain
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document.write( " mL of the desired 40% solution. \n" );
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Algebra.Com's Answer #346721 by lowtek(4)![]() ![]() ![]() You can put this solution on YOUR website! Let x = Amount Invested at 40% \n" ); document.write( "Let y = Amount Invested at 90% \n" ); document.write( " \n" ); document.write( "Amount Invested = $2.96219e-154 \n" ); document.write( "Total Income = $0 \n" ); document.write( " \n" ); document.write( "x + y = 2.96219e-154 \n" ); document.write( "x = 2.96219e-154 - y \n" ); document.write( " \n" ); document.write( "0.4x +0.9y = 0 \n" ); document.write( "40x +90y = 0 \n" ); document.write( " \n" ); document.write( "40(2.96219e-154 - y) +90y = 0 \n" ); document.write( "1.18488e-152 - 40y +90y = 0 \n" ); document.write( "50y = -1.18488e-152 \n" ); document.write( " \n" ); document.write( "y = $-2.36975e-154 Invested at 90% \n" ); document.write( " \n" ); document.write( "x = 2.96219e-154 - -2.36975e-154 \n" ); document.write( " \n" ); document.write( "x = $5.33194e-154 Invested at 40% \n" ); document.write( " |