document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=522162>Question 522162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the maximum possible area in square inches of a rectangle with a perimeter of 20 inches? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #346719 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=346719\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what is the maximum possible area in square inches of a rectangle with a perimeter of 20 inches?<BR>\n" );
document.write( "===================================<BR>\n" );
document.write( "Given: P = 2l + 2w = 20<BR>\n" );
document.write( "Solve for l in terms of w:<BR>\n" );
document.write( "l + w = 10 -> w = 10 - l<BR>\n" );
document.write( "The area of the rectangle is:<BR>\n" );
document.write( "A = l*w = l(10-l)<BR>\n" );
document.write( "The area will be a maximum where dA/dl = 0<BR>\n" );
document.write( "dA/dl = 0 = 10 - 2l<BR>\n" );
document.write( "This gives l = 5<BR>\n" );
document.write( "Therefore, the maximum area = 5*5 = 25 sq. in.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );